Monday, 10 March 2014


Two numbers form Amicable Pairs  if sum of proper divisors of  1st is equal to the 2nd and vice-versa.It is assumed that these two numbers should be distinct,

Example : Let two number 220 And 284 ,
      Sum of proper Divisor of 220 := 1+2+4+5+10+11+20+22+44+55+110 = 284
      Sum of Proper Divisor of 284 :=1+2+$+71+142=210 .
 That's Why 220 & 284 form amicable number pair .

Note : ( 220 , 284 ) smallest Amicable Number Pair . 

C Code to find Amicable Number in GIven Range : 

  1. #include<stdio.h>  
  2.  #include<conio.h>  
  3.  void main()  
  4.  {  
  5.    long int range, test, chk, div, sum, n1, n2;  
  6.    printf("\n\t Enter the Range to Check Amicable Numbers :-");  
  7.    scanf("%ld",&range);  
  8.    test = 0;  
  9.    while( ++test < range )  
  10.    {  
  11.        sum = div = 0;  
  12.        while( ++div <= (test / 2) )  
  13.        {  
  14.            if( test % div == 0 )  
  15.              sum += div;  
  16.        }  
  17.        chk = sum;  
  18.        sum = div = 0;  
  19.        while( ++div <= chk/2 )  
  20.        {  
  21.            if( chk % div == 0 )  
  22.              sum += div;  
  23.        }  
  24.        if( sum == test )  
  25.        {  
  26.          if( test == chk )  
  27.             continue;  
  28.          n1 = test;  
  29.          if( n1 == n2)  
  30.             continue;  
  31.          n2 = chk;  
  32.          printf("\t%d\t%d\n", n1, n2);  
  33.        }  
  34.    }  
  35.   getch();  
  36.  }

Its algorithm is very simple . We choose each number in given range & find sum of its divisor . & check it is amicable pair or NOT but keep in mind that this is slowest approach to do find amicable number . Now Open your mind & Improve this program . (Y)


THANK YOU...........


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